Integrand size = 27, antiderivative size = 27 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}+\frac {(3-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{8 d^3 f \left (1-c^2 x^2\right )}-\frac {b c (3-m) (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{8 d^3 f^2 (2+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{4 d^3 f^2 (2+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {(1-m) (3-m) \text {Int}\left (\frac {(f x)^m (a+b \text {arccosh}(c x))}{d-c^2 d x^2},x\right )}{8 d^2} \]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}-\frac {(b c) \int \frac {(f x)^{1+m}}{(-1+c x)^{5/2} (1+c x)^{5/2}} \, dx}{4 d^3 f}+\frac {(3-m) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^2} \, dx}{4 d} \\ & = \frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}+\frac {(3-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{8 d^3 f \left (1-c^2 x^2\right )}+\frac {(b c (3-m)) \int \frac {(f x)^{1+m}}{(-1+c x)^{3/2} (1+c x)^{3/2}} \, dx}{8 d^3 f}+\frac {((1-m) (3-m)) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{d-c^2 d x^2} \, dx}{8 d^2}-\frac {\left (b c \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\left (-1+c^2 x^2\right )^{5/2}} \, dx}{4 d^3 f \sqrt {-1+c x} \sqrt {1+c x}} \\ & = \frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}+\frac {(3-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{8 d^3 f \left (1-c^2 x^2\right )}+\frac {((1-m) (3-m)) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{d-c^2 d x^2} \, dx}{8 d^2}-\frac {\left (b c \sqrt {1-c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\left (1-c^2 x^2\right )^{5/2}} \, dx}{4 d^3 f \sqrt {-1+c x} \sqrt {1+c x}}+\frac {\left (b c (3-m) \sqrt {-1+c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\left (-1+c^2 x^2\right )^{3/2}} \, dx}{8 d^3 f \sqrt {-1+c x} \sqrt {1+c x}} \\ & = \frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}+\frac {(3-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{8 d^3 f \left (1-c^2 x^2\right )}-\frac {b c (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{4 d^3 f^2 (2+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {((1-m) (3-m)) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{d-c^2 d x^2} \, dx}{8 d^2}-\frac {\left (b c (3-m) \sqrt {1-c^2 x^2}\right ) \int \frac {(f x)^{1+m}}{\left (1-c^2 x^2\right )^{3/2}} \, dx}{8 d^3 f \sqrt {-1+c x} \sqrt {1+c x}} \\ & = \frac {(f x)^{1+m} (a+b \text {arccosh}(c x))}{4 d^3 f \left (1-c^2 x^2\right )^2}+\frac {(3-m) (f x)^{1+m} (a+b \text {arccosh}(c x))}{8 d^3 f \left (1-c^2 x^2\right )}-\frac {b c (3-m) (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{8 d^3 f^2 (2+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c (f x)^{2+m} \sqrt {1-c^2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{4 d^3 f^2 (2+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {((1-m) (3-m)) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{d-c^2 d x^2} \, dx}{8 d^2} \\ \end{align*}
Not integrable
Time = 12.27 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.07 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx \]
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Not integrable
Time = 1.21 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00
\[\int \frac {\left (f x \right )^{m} \left (a +b \,\operatorname {arccosh}\left (c x \right )\right )}{\left (-c^{2} d \,x^{2}+d \right )^{3}}d x\]
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Not integrable
Time = 0.28 (sec) , antiderivative size = 57, normalized size of antiderivative = 2.11 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int { -\frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c^{2} d x^{2} - d\right )}^{3}} \,d x } \]
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Timed out. \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\text {Timed out} \]
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Not integrable
Time = 0.72 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.19 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int { -\frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c^{2} d x^{2} - d\right )}^{3}} \,d x } \]
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Not integrable
Time = 0.30 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.15 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int { -\frac {{\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (c^{2} d x^{2} - d\right )}^{3}} \,d x } \]
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Not integrable
Time = 3.06 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.07 \[ \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\left (d-c^2 d x^2\right )^3} \, dx=\int \frac {\left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )\,{\left (f\,x\right )}^m}{{\left (d-c^2\,d\,x^2\right )}^3} \,d x \]
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